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What would be the molality of 60% (mass/...

What would be the molality of 60% (mass/mass) aqueous solution of `CH_(3)COOH`? (Molar mass of `CH_(3)COOH = 60 g mol^(-1)` )

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The correct Answer is:
2
60% (mass/mass) means
100 gms of solution has 60 gm of `CH_(3)COOH`
`implies 40 gm` of solvent contains 60 gm of `CH_(3) COOH`
Molality, `m = (60)/(60) xx (1000)/(40) = 1.506 ~~ 1.51 m`
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