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The periodic time of a simple pendulum, ...

The periodic time of a simple pendulum, oscillating in air is T. But if the bob of the simple pendulum is completely immersed in a nonviscous liquid, whose density is `(1)/(20)` th of the material of the bob, then its new period will be

A

`2T sqrt((1)/(10))`

B

`4 T sqrt((1)/(15))`

C

`4 T sqrt((1)/(14))`

D

`2T sqrt((1)/(14))`

Text Solution

Verified by Experts

The correct Answer is:
B
`T=2pi sqrt(l/g)& T'=2pi sqrt((1)/(g-(g//16))) " " ( :' "Buoyancy" = (mg)/(16))`
`:.T=Txx(1)/(sqrt(1-1/16))=4Txx sqrt((1)/(15))`
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