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Two radioactive substance A and B have d...

Two radioactive substance `A` and `B` have decay constants `5 lambda` and `lambda` respectively. At `t=0` they have the same number of nuclei. The ratio of number of nuclei of nuclei of `A` to those of `B` will be `(1/e)^(2)` after a time interval

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The correct Answer is:
`0.50`
`N_(A) = N_(0) e^(-5 lamda t)" " N_(B) = N_(0) e^(- lamda t)`
`(N_(A))/(N_(B)) = (1)/(e^(2)) rArr (e^(-5lamda t))/(e^(-lamda t)) = (1)/(e^(2)) rArr 4 lamda t = 2`
`t = (1)/(2 lamda)`
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