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The increasing order of nucleophilicity ...

The increasing order of nucleophilicity of the following nucleophiles is:
(a) `CH_(3)CO_(2)^(-)` (b) `H_(2)O` (c) `CH_(3)SO_(3)^(-)` (d) `overset(O)H`

A

`(b) lt (c) lt (d) lt (a)`

B

`(d) lt (a) lt (c) lt (b)`

C

`(b) lt (c) lt (a) lt (d)`

D

`(a) lt (d) lt (c) lt (b)`

Text Solution

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The correct Answer is:
To determine the increasing order of nucleophilicity among the given nucleophiles: \( CH_3CO_2^- \), \( H_2O \), \( CH_3SO_3^- \), and \( OH^- \), we will analyze each nucleophile based on their charge and resonance stability. ### Step-by-Step Solution: 1. **Identify the Nucleophiles**: - \( CH_3CO_2^- \) (acetate ion) - \( H_2O \) (water) - \( CH_3SO_3^- \) (methyl sulfonate ion) - \( OH^- \) (hydroxide ion) 2. **Charge Consideration**: - Nucleophiles with a negative charge are generally stronger than neutral nucleophiles. Therefore, \( H_2O \) will be the weakest nucleophile among the four. 3. **Stability of Negative Charge**: - The stability of the negative charge affects nucleophilicity. A more stable negative charge corresponds to a weaker nucleophile. - **Resonance Structures**: - **For \( CH_3CO_2^- \)**: The negative charge can be delocalized over two oxygen atoms, giving it two resonance structures. - **For \( CH_3SO_3^- \)**: The negative charge can be delocalized over three oxygen atoms, providing it with three resonance structures, which makes it more stable than \( CH_3CO_2^- \). - **For \( OH^- \)**: The hydroxide ion has no resonance stabilization, making it a strong nucleophile. 4. **Comparing Nucleophilicity**: - Since \( OH^- \) has no resonance stabilization, it is the strongest nucleophile. - \( CH_3CO_2^- \) is next, as it has some resonance stabilization but is less stable than \( CH_3SO_3^- \). - \( CH_3SO_3^- \) is the weakest nucleophile due to its highly stabilized negative charge from resonance. - Finally, \( H_2O \) is the weakest nucleophile since it is neutral. 5. **Final Order**: - The increasing order of nucleophilicity is: \[ H_2O < CH_3SO_3^- < CH_3CO_2^- < OH^- \] ### Conclusion: Thus, the increasing order of nucleophilicity is: \[ H_2O < CH_3SO_3^- < CH_3CO_2^- < OH^- \]

To determine the increasing order of nucleophilicity among the given nucleophiles: \( CH_3CO_2^- \), \( H_2O \), \( CH_3SO_3^- \), and \( OH^- \), we will analyze each nucleophile based on their charge and resonance stability. ### Step-by-Step Solution: 1. **Identify the Nucleophiles**: - \( CH_3CO_2^- \) (acetate ion) - \( H_2O \) (water) - \( CH_3SO_3^- \) (methyl sulfonate ion) ...
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