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The ratio of te shortest wavelength of t...

The ratio of te shortest wavelength of two spectral series of hydrogen spectrum is found to be about 9. The spectral series are:

A

Balmer and Barckett

B

Paschen and Pfund

C

Brackett and Pfund

D

Lyman and Paschen

Text Solution

Verified by Experts

The correct Answer is:
D
The shortest wavelength for Lyman series
`(1)/(lamda_("Lyman")) = R_(H) [(1)/(1^(2)) - (1)/(oo^(2))]`
`lamda_("Lyman") = (1)/(R_(H))`
The shortest wavelength for paschen series
`(1)/(lamda_("Paschen")) = R_(H) [(1)/(3^(2)) - (1)/(oo^(2))]`
`lamda_("Paschen") = (9)/(R_(H))`
`(lamda_("Paschen"))/(lamda_("Lyman")) = (9//R_(H))/(1//R_(H)) = 9`
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