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A message single of frequency 100 MHz an...

A message single of frequency 100 MHz and peak voltage 100 V is used to execute amplitude modulation on a carrier wave of frequency 300 GHz and peak voltage 400 V. The modulation index and difference between the two side band frequencies are:

A

`4, 1 xx 10^(8)` Hz

B

`0.25, 2 xx 10^(8)` Hz

C

`4.2 xx 10^(8)` Hz

D

`0.25, 1 xx 10^(8)` Hz

Text Solution

Verified by Experts

The correct Answer is:
B
Modulating index = m =`("Amplitude of m assage signal")/("Amplitude of Carrier signal") =1/4 = 0.25`
Three frequency are obtained, `f_("carrier"), f_("carrier") + f_("massage")`
So, Board witih `=2f_("massage") = 200` MHz
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