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A block of mass 5 kg is (i) pushed in ca...

A block of mass 5 kg is (i) pushed in case (A) and (ii) pulled in case (B), by a force F = 20 N, making an angle of `30^(@)` with the horizontal, as shown in the figures. The coefficient of friction between the block and floor is `mu=0.2` . The difference between the accelerations of the block, in case (B) and case (A) will be: `(g=10ms^(-2))`

A

`0ms^(-2)`

B

`3.2ms^(-2)`

C

`0.4ms^(-1)`

D

`0.8 ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`(A)" "(B)`
`f_(1)=mu(mg+F sin theta)" "f_(2)=mu(mg-f sin theta )`
`a_(1)=(F.cos 30^(@)-f_(1))/m" "a_(2)(Fcos 30^(2)-f_(2))/m`
`a_(1)=(Fcos theta-mu mg -mu F sin theta)/m" a_(2)=(Fcos mumg+muFsin theta)/m`
`a_(2)-a_(1)=(2muF sin theta)/m" =(2xx0.2xx20xx1)/(5xx2)=0.8m//s^(2)`
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