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In an amplitude modulator circuit, the c...

In an amplitude modulator circuit, the carrier wave is given by, `C(t)=4sin (20000pit)` while modulating signal is given by, `m(t)=2 sin (2000pit)`. . The values of modulation index and lower side band frequency are:

A

0.3 and 9 kHZ

B

0.5 and 10 kHz

C

0.4 and 10 kHz

D

0.5 and 9 kHz

Text Solution

Verified by Experts

The correct Answer is:
D

L.S.B `=omega_(c)-omega_(m)=(20000-2000)pi=18000pi` rad/s
So `(18000pi)/(2pi)=9000Hz`
Modulation index `=(A_(m))/(A_(c))=0.5`
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