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The molar solubility iof Cd(OH)(2) is 1....

The molar solubility iof `Cd(OH)_(2)` is `1.84xx10^(-5)M` in water. The expected solubiliyt of `Cd(OH)_(2)` in a buffer solution of `pH=10` is `2.49xx10^(-x)M`. The numerical value of x is.

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The correct Answer is:
6
`Cd(OH)_(2) Cd^(+2)+2OH^(-)`
`K_(sp)=[Cd^(+2)][OH^(-)]^(2)`
Solubility `s=[Cd^(+2)]=(K_(sp))/([OH^(-)]^(2))`
pH of the buffer `=10`
`pOH=4, [OH]=10^(-4)`
`K_(sp)=4S^(3)=4(1.84xx10^(-5))^(3)`
`[Cd^(+2)]_(f)=(4[1.84xx10^(-5)]^(3))/((10^(-8))]=(4xx6.23x10^(-15))/(10^(-8))=2.49xx10^(-6)M`
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