25 g of an unknown hydrocarbon contains 24 g of carbon. 25 g of this hydrocarbon on burning produces x gm of `H_(2)O`. The numerical value of x is_____.

Answer

9

Explanation

`C_(x)H_(y)+(x+y//4)O_(2)toxCo_(2)+h//2H_(2)O`
`25 g" "88g" "9gm`
`" "2 "moles" " "1//2 "mole"`
(Molar ratio of C and H in Hydrocarbon)
`x/(y//2)=2/(1//2)`
`(2x)/y=4/1" " :." " x/y=2/1`
Hence, 25 g of the Hydrocarbon have 24 g of the Carbon and 1 g of the Hydrogen