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Let f(x)=5-|x-2| and g(x)=|x+1|, x in R....

Let `f(x)=5-|x-2| and g(x)=|x+1|, x in R`. If f(x)n artains maximum value at `alpha` ang g(x) attains minimum value of `beta`, then `underset(xto-alpha beta)lim((x-1)(x^(2)-5x+6))/(x^(2)-6x+8)` is equal to

A

`-1/2`

B

`-3/2`

C

`1/2`

D

`3/2`

Text Solution

Verified by Experts

The correct Answer is:
C
`alpha=2,beta=-1`
`lim_(xto2)((x-1)(x-2)(x-3))/((x-4)(x-2))=(-1)/(-2)=1/2`
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