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The stopping potential V(0) (in volt) a...

The stopping potential `V_(0)` (in volt) as a function of frequency (v) for a sodium emitter, is shown in the figure. The work function of sodium, from the data plotted in the figure, will be:
(Given : Planck’s constant)
`(h) = 6.63 xx10^(-34)Js" electron charge "e=1.6xx10^(-19)C`)

A

1.95 eV

B

2.12 eV

C

1.66 eV

D

1.82

Text Solution

Verified by Experts

The correct Answer is:
C
`W=hv_(0)=6.63xx10^(-34)xx10^(14)xx4J`
`W=6.63xx10^(20)Jxx4=(4xx6.63xx10^(-20))/(1.6xx10^(-19))eV=1.66eV`
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Knowledge Check

  • The work function of a photoelectric material is 3.3 V. the threshold frequency will be equal to [Given that h=6.6xx10^(-34)Js ]

    A
    `8.0xx10^(14)Hz`
    B
    `8.0xx10^(34)Hz`
    C
    `5.0xx10^(15)Hz`
    D
    `5.0xx10^(19)Hz`

  • The wavelength of th first spectral line of sodium 5896 Å . The fisrt excitation potential of sodium atomm will be (Planck's constant h=6.63xx10^(-34) J-s)

    A
    `4.2 V`
    B
    `3.5 V`
    C
    `2.1 V`
    D
    None of these

  • Calculate the energy in joule corresponding to light of wavelength 45 nm (Planck.s constant h=6.63xx10^(-34) Js, speed of light c=3xx10^(8) ms^(-2))

    A
    `6.67xx10^(12)`
    B
    `4.42xx10^(-13)`
    C
    `4.42xx10^(-18)`
    D
    `6.67xx10^(12)`

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    If the work function of a and is 3 eV, calculate the threshold wavelength of that metal. (Velocity of light =3xx10^(8)m//s Planck's constant= 6.63xx10^(-34)J-s,1eV=1.6xx10^(-19) )

    Calculate the wavelength of light incident on a material of work function 2.0 eV if the stopping potential is 1.0 V . Given h = 6.625 xx10^(-34) Js and mass of electron =9.1xx10^(-31) kg

    Calculate the energy in joule corresponding to light of wavelength 45 nm (Planck.s constant h=6.63xx10^(-34) Js, speed of light c=3xx10^(8) ms^(-2))

    A student performs an experiment on photoelectric effect using two materials A and B. A plot of stopping potential (V_(0)) vs freqency (v) is as shown in the figure. The value of obtained from the experiment for both A and B respectively is (Given electric charge of an electron =1.6xx10^(-19)C)

    The value of Planck's constant is 6.62618 xx 10^(-34)Js . The number of significant figures in it is

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