Home
Class 12
PHYSICS
A person of mass M is setting on a swing...

A person of mass M is setting on a swing of length L and swinging with an angular amplitude `theta_(0)` if the person stands up when the swing passes through its lowest point, the work done by him, assuming that his centre of mass moves by a distance `l(lt lt L)`

A

`Mgl`

B

`Mgl(1-theta_(0)^(2))`

C

`Mgl(1+(theta_(0)^(2))/(2))`

D

`Mgl(1+theta_(0)^(2))`

Text Solution

Verified by Experts

The correct Answer is:
D

`W=M(g+a)l," "a=omega^(2)L`
`(1)/(2)Momega^(2)L^(2)=Mg(1-cos theta_(0))," "omega^(2)L=2g(1-cos theta_(0))`
`W=M[g+2g(1-cos theta_(0))]l, " "w=M[g+2g-2g cos theta_(0)]l`
`W=mg[3-2costheta_(0)]l," "W=mg[3-2(1-(theta_(0)^(2))/(2))]l`
`W=Mg[3-2+2xx(theta_(0)^(2))/(2)]l`
`Wg[1+theta_(0)^(2)]l," "W=Mgl[1 +theta_(0)^(2)]`
Promotional Banner

Similar Questions

Explore conceptually related problems

A simple pendilum with bob of mass m and length l is held in position at an angle theta with t he verticle. Find its speed when it passes the lowest position.

A simple pendulum with a bob of mass m and a conducting wire of length L, swings under gravity with an angular amplitude 2theta . If the horizontal component of the earth's magnetic field perpendicular to the plane of motion of the pendulum is B, then the maximum emf induced across the pendulum is

A sphere of mass m attached with the free end of a steel wire of length l swings in the veritcle plane form the horizontal positon. Elastic energy should in the wire in the vericle positon is

A uniform rod of length l is spinning with an angular velocity omega=2v/l while its centre of mass moves with a velocity v . Find the velocity of the end of the rod.

A simple pendulum with a bob of mass 'm' swings with angular amplitude of 60^@ . When its angular displacement is 30^@ , the tension in the strings would be

A sphere of mass m attached with the free end of a steel wire of length l swings in the veritical plane form the horizontal positon. Elongation of the wire in the vericle positon is

A person of mass m is standing in a lift. Find his apparent weight when the lift is : moving downward with uniform acceleration a(lt g)

A simple pendulum with a bob of mass m swings with an angular amplitude of 40^@ . When its angular displacement is 20^@ , the tension in the string is greater than mg cos 20^@