The transfer characteristic curve of a transistor, having input and output resistance `100Omega and 100kOmega` respectively, is shown in the figure. The Voltage and Power gain, are respectively:

Options

A. `2.5xx10^(4), 2.5xx10^(6)`
B. `5xx10^(4), 2.5xx10^(6)`
C. `5xx10^(4), 5xx10^(5)`
D. `5xx10^(4), 5xx10^(6)`

Answer

B

Explanation

`R_(i)=100Omega," "R_("o")=100xx10^(3)Omega`
`"Voltage gain"=("Change in output voltage")/("Change in input voltage")`
`"Voltage gain"=(DeltaV_(0))//(DeltaV_(i))`
`=(DeltaI_(c)xxR_(0))/(DeltaI_(b)xxR_(i))," "A_(V)=5xx10^(4)`
`"Power gain "=("change in output power")/("change in input power")=(DeltaV_(0).DeltaI_(c))/(DeltaV_(i).DeltaI_(b))=(DeltaI_(c).R_(0).DeltaI_(c))/(DeltaI_(b).R_(i)xxDeltaI_())=((DeltaI_(c))/(DeltaIb))^(2)xx(R_(0))/(R_(i))`
`=(5xx10^(-3))/(100xx10^(-6))^(2)xx(100xx10^(3))/(100)=(25xx10^(-6))/(10^(-8))xx10^(3)`
`"Power gain " =25xx10^(5)=2.5xx10^(6)`