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Find the quantum number n corresponding ...

Find the quantum number `n` corresponding to the excited state of `He^(+)` ion of on transition to the ground state that ion emits two photons in succession with wavelengths `108.5` and `30.4nm`.

A

`n=6`

B

`n=5`

C

`n=7`

D

`n=4`

Text Solution

Verified by Experts

The correct Answer is:
B
Total energy `E=((1240)/(108.5)+(1240)/(30.4))eV`
`13.6xxZ^(2)(1-(1)/(n^(2)))=E" "therefore" "13.6xx4(1-(1)/(n^(2)))=1240((138.9)/(108.5xx30.4)) therefore n=5`
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