Home
Class 12
CHEMISTRY
The molar solubility of Al(OH)(3) in 0.2...

The molar solubility of `Al(OH)_(3)` in 0.2 M NaOH solution is `x xx 10^(-22)"mol/L"`. Given that, solubility product of `Al(OH)_(3)=2.4xx10^(-24)`. What is numerical value of x?

Text Solution

Verified by Experts

The correct Answer is:
3
`K_(sp)=[s][0.2]^(2)`
`[s]=24xx10^(-24)`
`=3xx10^(-22)//[0.2]^(3)`
Promotional Banner

Similar Questions

Explore conceptually related problems

What is the molar solubility of Al(OH)_(3) in 0.2 M NaOH solution? Given that, solubility product of Al(OH)_(3) = 2.4 xx 10^(-2)

molar solubility of Cd(OH)_(2)(Ksp=2.5xx10^(-14)) in 0.1 M KOH solution is :-

The solubility of Sb_(2)S_(3) in water is 1.0 xx 10^(-8) mol/litre at 298 K. What will be its solubility product:

The solubility of Sb_(2)S_(3) in water is 1.0 xx 10^(-5) mol/letre at 298K. What will be its solubility product ?

The molar solubility of Zn(OH)_2 in 0.1 M NaOH solution is x xx 10^(-18)M. The value of x is _________. (Nearest integer) (Given: The solubility product of Zn(OH)_2" is " 2 xx 10^(-20) )

The molar solubility of M(OH)_(3) in 0.4 M M(NO_(3))_(3) solution inters of solubility product of M(OH)_(3)

The molar solubility iof Cd(OH)_(2) is 1.84xx10^(-5)M in water. The expected solubiliyt of Cd(OH)_(2) in a buffer solution of pH=10 is 2.49xx10^(-x)M . The numerical value of x is.

The solubility product of BaCl_(2) is 3.2xx10^(-9) . What will be solubility in mol L^(-1)

The solubility of a saturated solution of calcium fluoride is 2xx10^(-4) mol/L. Its solubility product is

pH of saturated solution of Al(OH)_3 is 9 . The solubility product (K_sp) of Al(OH)_3 is