The product of n consecutive natural num...

The product of `n` consecutive natural numbers is always divisible by

A

divisible by n!

B

divisible by (n+1)!

C

odd

D

Multiple of 4

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The correct Answer is:

A

Product of any consecutive positive integers `=(r+1)(r+2)...(r+n)`
Then `((r+1)...(r+n))/(n!)=((n+r)!)/(r! n!)=""^(n-r)C_(n)="integer"`

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