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If b(y-alpha x)(y-alpha^(2) x)" is ident...

If `b(y-alpha x)(y-alpha^(2) x)" is identical to "ax^(2)+2hxy+by^(2)," then "(a+b)/(h)+(8h^(2))/(ab)" is"`

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The correct Answer is:
6
`alpha+alpha^(2)=(-2h)/(b) .........(1)`
And `alpha.alpha^(2)=a/b rArr alpha=(a/b)^(1//3) ........(2)`
Substituting value of `alpha` from (ii) in (i), we get : `(a/b)^(1//3)+(a/b)^(2//3) alpha=(-2h)/(b)`
Cubing both sides, we get : `a/b+a^(2)/b^(2)+3(a/b) [(a/b)^(1//3)+(a/b)^(2//3)]=(-8h^(3))/(b^(3))`
`rArr a/b+a^(2)/b^(2)-(6ah)/(b^(2))=-(8h^(3))/(b^(3)) rArr ab^(2)+a^(2)b-6abh =-8h^(3)`
`rArr (b+a)/(h)+(8h^(2))/(ab)=6`
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