A piece of wood of mass 0.3 kg is droppe...

A piece of wood of mass 0.3 kg is dropped from the top of a 20 m height building. At the same time, a bullet of mass 0.2 kg is fired vertically upward, with a velocity 80m/s from the ground. The bullet strikes the wood and gets embedded in it. Then, the maximum height to which the combined system reaches above the top of the building before falling below is: (`g= 10m//s^2`)

20m

43.2 m

35m

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The correct Answer is:

`X_(cm) , i=(0.3 xx 20)/(0.5) = 12m `
` V_(cm), i=(0.2 xx 80)/(0.5) = 32m//s`
` H_(max)` of centre of mass
above `P = (32 xx 32)/(2 xx 10) = 51.2 m`
Height above top of building = 51.2 - 8 = 43.2 m

A wooden block of mass 10 g is dropped from the top of a tower 100 m high. Simultaneously, a bullet of mass 10 g is fired from the foot of the tower vertically upwards with a velocity of 100 m//s . If the bullet is embedded in it, how high will the block rise above the top of tower before it starts falling? (g=10m//s^2)

`75m`

`85m`

`80m`

`10m`

A wooden block of mass 20g is dropped from the top of the cliff 50 m high. Simultaneously a bullet of mass 20 g is fired from the foot of the cliff upwards with a velocity 25 ms^(-1) . The bullet and the wooden block will meet each other after time :

0.5s

A wooden block of mass 10 gm is dropped from the top of a tower 100m high. Simultaneously, a bullet of mass 10 gm is fired from the foot of the tower vertically upwards with a velocity of 100m//sec , figure. If the bullet is embedded in it, how high will it rise above the tower before it starts falling ? (Consider g=10m//sec^(2))

`80m`

`85 m`

`75 m`

`10 m`

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A wooden block of mass 20g is dropped from the top of the cliff 50 m high. Simultaneously a bullet of mass 20 g is fired from the foot of the cliff upwards with a velocity 25 ms^(-1) . The bullet and the wooden block will meet each other after time :

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