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A string of length 1m and mass 5g is fix...

A string of length 1m and mass 5g is fixed at both ends. The tension in the string is 12.5 N. The string is set into vibration using an external vibrator of frequency 100 Hz. The separation between successive nodes on the string (in m) is ______ .

Text Solution

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`V = sqrt(T/mu) = sqrt((12.5)/(5 xx 10^(-3) )) = sqrt(2500) = 50 ms^(-1)`
` f = 100 Hz`
` lamda = V/f = 50/100 = 0.5 m`
`lamda/2 = 25 cm`
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