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A charges Q is placed at each of the two...

A charges Q is placed at each of the two opposite corners of a square. A charge q is placed to each of the other two corners. If the resultant force on each charge q is zero, then

A

`Q=-2sqrt2q`

B

`Q=sqrt2q`

C

`Q=-sqrt2q`

D

Q=-2q

Text Solution

Verified by Experts

The correct Answer is:
A
The force on charge is zero, therefore
`F_(qQ) cos 45^@+F_(qQ) cos 45^@ +F_(Q Q)=0`

`2F_(qQ)1/sqrt2+F_(Q Q)=0`
`1/(4piepsilon_0)[(qQ)/a^2 sqrt2 + (Q Q)/(2a^2)]=0`
`therefore Q=-2sqrt2q`
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