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Five moles of hydrogen (gamma = 7//5), i...

Five moles of hydrogen `(gamma = 7//5)`, initially at `STP`, is compressed adiabatically so that its temperature becomes `400^(@)C`. The increase in the internal energy of the gas in kilojules is `(R = 8.30 J//mol-K)`

A

21.55

B

41.5

C

65.55

D

80.55

Text Solution

Verified by Experts

The correct Answer is:
B
`C_p/C_v=gamma=7/5`
Work done =` (muR)/(gamma-1)xxDeltaT=(8.3xx400xx5)/(7/5-1)`
Work done = change in internal energy ( `because Delta Q=0` for adiabatic process)
`therefore` Change or increase in internal energy =41.5 kJ
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