Home
Class 12
PHYSICS
A satellite is revolving round the earth...

A satellite is revolving round the earth with orbital speed `v_(0)` if it is imagined to stop suddenly the speed with which it will strike the surface of the earth would be `(v_(e)` - escape speed of a body from earth s surface)

A

`v_e^2/v_0`

B

`v_0`

C

`sqrt(v_e^2 -v_0^2)`

D

`sqrt(v_e^2 -2v_0^2)`

Text Solution

Verified by Experts

The correct Answer is:
D
Let r be the radius of the satellite. Then `v_0^2=(GM)/r`
Applying conservation of mechanical energy between points A and B we have:
`1/2mv^2 =-(GMm)/r-(-(GMm)/R)`
`v^2=(2GM)/R-(2Gm)/r=v_e^2-2v_0^2`
`therefore v=sqrt(v_e^2-2v_0^2)` .
Promotional Banner

Similar Questions

Explore conceptually related problems

The escape speed of a body from the earth depends upon

A satellite is revolving round the earth in an elliptical orbit. Its speed will be

A satellite is revolving around the earth. Ratio of its orbital speed and escape speed will be.

A satellite revolves around the earth in an elliptical orbit. Its speed is

The escape speed of a body from the surface of the Earth is

A satellite is revolving around earth in a circular orbit at a uniform speed v . If gravitational force suddenly disappears , speed of the satellite will be

The value of escape speed from the surface of earth is

A satellite orbiting close to earth surface will escape, if