In the circuit shown, the key is inserte...

In the circuit shown, the key is inserted at t=0. Charge which passes in the circuit in one time constant is :

A

`L/"VR"`

B

`(LeV)/R^2`

C

`(LV)/(R^2e)`

D

`(L^2V)/(Re)`

Verified by Experts

The correct Answer is:

C

`i=V/R(1-e^("-t"//tau))`
`q=int_0^tau idt =V/R (1-e^("-t"//tau)/(-1//tau))_0^tau =V/R tau/e =(LV)/(eR^2)`

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