If for the heterogeneous equilibriumCaCO...

If for the heterogeneous equilibrium`CaCO_3(s) hArr CaO(s) +CO_2(g)` , the equilibrium constant `K_c=1`, at 1 atm what would be the temperature of the reaction?

A

`T=(DeltaS^@)/(DeltaH^@)`

B

`T=(DeltaH^@)/(DeltaS^@)`

C

`T=(DeltaH^@)/(DeltaG^@)`

D

`T=(DeltaG^@)/(DeltaH^@)`

Verified by Experts

The correct Answer is:

B

`DeltaG^@=-2.303 RT log K_C` and `DeltaG^@=DeltaH^@-TDeltaS^@`
`0=DeltaH^@-TDeltaS^@`
`T=(DeltaH^@)/(DeltaS^@)`

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