An aqueous solution of 6.3 g of oxalic acid dihydrate is made upto 250 mL. The volume of 0.1 N NaOH required to completely neutralise 10 mL of this solution is :

Answer

D

Explanation

Equivalents of oxalic acid in 250 mLl=`(6.3xx2)/126`=0.1
Equivalents of oxalic acid in 10 ml = `0.1/250xx10=1/250`
Equivalents of NaOH=`(0.1xxV(ml))/1000 therefore (0.1xxV)/1000=1/250`
V=40 ml.