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If the continued product of three number...

If the continued product of three numbers in GP is 216 and the sum of their products in pairs is 156, then find the sum of three numbers.

Text Solution

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The correct Answer is:
B
Let numbers are `a/r`, a, ar
Then `a/r xx a xx ar =216 rArr a=6`
And sum of products in pair =156
`rArr a/rxxa+axxar+arxxa/r=156 rArr 3r^2-10r+3=0 rArr r=1/3` or 3
So required numbers are 18,6,2 or 2, 6 ,18
Hence, the sum of numbers is 26.
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