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Two discs have same mass and thickness. ...

Two discs have same mass and thickness. Their materials are of densities `rho_(1)` and `rho_(2)` . The ratio of their moment of inertia about central axis will be

A

`rho_(1):rho_(2)`

B

`rho_(1)rho_(2):1`

C

`1:rho_(1)rho_(2) `

D

`rho_(2):rho_(1)`

Text Solution

Verified by Experts

The correct Answer is:
D
M.I. of disc `I=(1)/(2)MR^(2)=(1)/(2)M((M)/(pi rho t))=(1)/(2) (M^(2))/(pi rho t)`
`therefore I prop (1)/(rho)" " `[ If M and t are constant]
`rArr (I_(1))/(I_(2))=(rho_(2))/(rho_(1)) rArr I_(1): I_(2)=rho_(2):rho_(1)`
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