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The acceleration due to gravity on the s...

The acceleration due to gravity on the surface of the moon is `(1)/(6)th` of that on the surface of earth and the diameter of the moon is one-fourth that of earth. The ratio of escape velocities on earth and moon will be

A

`(sqrt(6))/(2)`

B

`sqrt(24)`

C

3

D

`(sqrt(3))/(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`v_(e)=sqrt(2gR), ((v_(e))_("Earth"))/((v_(e))_("moon"))=sqrt((g_(E)R_(E))/(g_(m)R_(m)))=sqrt(24)`
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