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A simple potentiometer circuit is shown ...

A simple potentiometer circuit is shown in the figure. The internal resistance of the battery is negligible. AB is a uniform wire of length 100cm and resistance `2Omega` What would be the length AC for zero galvanometer deflection (in mm)?

Text Solution

Verified by Experts

The correct Answer is:
825
`I=(4)/(2.4+2)=(4)/(4.4)=(1)/(1.1)=(10)/(11)`
If `AC=x`
Then `R_(AC)=(x)/(50)Omega`
`(10)/(11)xx(x)/(50)=1.5 rArr x=1.5xx5xx11=82.5cm`
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