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8.7 gm of pure MnO(2) is heated with a...

8.7 gm of pure `MnO_(2)` is heated with an excess of HCl and the gas evolved is passed into a solution of KI. The amount of `I_(2)` liberated is [Atomic mass O = 16, Mn = 55]

A

0.2 mole

B

25.4 gm

C

15.4 gm

D

7.7 gm

Text Solution

Verified by Experts

The correct Answer is:
B
`MnO_(2)+4HCltoMnCl_(2)+Cl_(2)+H_(2)O`
`Cl_(2)+2KItoI_(2)+2KCI`
Moles of `MnO_(2)=(8.7)/87=0.1`
Moles of `Cl_(2)=0.1`
Moles of `I_(2)=0.1`
Mass of `I_(2)=0.1xx254=25.4` gm
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