Given a system of equations in `x,y,z : x+y+z=6,x+2y+3z=10` and `x+2y+az=b`. If this system has infinite number of solutions, then `a^(2)+b=`……….

Answer

19

Explanation

From first two equations, we get `x=x+2 and y=4-2z
So the third equation `rArr(z+2)+2(4-2z)+az=b`
`rArr(a-3)z=b-10`
This will be true for all real z if a=3 and b=10