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A gaseous mixture consists of 16 g of he...

A gaseous mixture consists of 16 g of helium and 16 g of oxygen. Find `gamma` for the mixture.

A

`23/29`

B

`47/23`

C

`29/23`

D

`47/29`

Text Solution

Verified by Experts

The correct Answer is:
D
`C _(v mix ) = (n _(v _(1))C _(v _(1))+ n _(2) C _(v_(2)))/(n _(1 ) + n _(2))=((4 ) ((3R)/(2)) + ((1)/(2)) ((5R)/(2)))/(4+ (1)/(2))= (29R)/(18)`
`C _(P mix ) = (47R)/(18)," "So, " " (C _(p))/( C _(v)) = (47)/(29)`
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