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For the reaction, 2A (s) + 2B (g)to C (g...

For the reaction, `2A (s) + 2B (g)to C (g) + D(s) at 298K`
`Delta U ^(@) =-10.5KJ and Delta S ^(@)=-44.10 JK^(-1)`
Calculate `Delta G ^(@)` for the reaction (in Joules).

Text Solution

Verified by Experts

The correct Answer is:
`164.8`
`2A (s ) + 2B(g) to C (g)+ D(s)`
`Delta n _(g)=1-2 =-1, Delta G ^(@) = Delta H ^(@) - T Delta S ^(@), " " Delta H ^(@)=Delta U ^(@) + Delta n _(g) RT`
`Delta H ^(@) =-10 . 5 kJ + (-1) (8.314) xx 10^(-3) kJ ) (298K ) =-10.5 - 2.48 =-12.977kJ`
`Delta G ^(@) = Delta H ^(@) - T Delta S ^(@)=12.977kJ -298 (-44.1 xx 10^(-3)kJ ) =0.1648kJ = 164.8` Joules.
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