Let x (1) , x (2), x (3) be the points w...

Let `x _(1) , x _(2), x _(3)` be the points where `f (x) = | 1-|x-4||, x in R` is not differentiable then `f (x_(1))+ f(x _(2)) + f (x _(3))=`

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The correct Answer is:

1

Function is not differentiable at `x =3, 4,5`
So,` f (3) + f(4) + f(5)`
`0 + 1+0=1`

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