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The time period of revolution of electro...

The time period of revolution of electron in its ground state orbit in a hydrogen atom is `1.60 xx 10^(-16)` second. The time period of revolution of the electron in its first excited state in a `Li^(++)` ion is:

A

`1.42 xx 10^(-16) s`

B

`1.20 xx 10^(-16) s`

C

`2.32 xx 10^(-16) s`

D

`2.42 xx 10^(-16) s`

Text Solution

Verified by Experts

The correct Answer is:
A

`T = (2 pi r)/(v)`, `T = (2 pi a_(0))/(v_(1)) (n^(2))/(z). (n)/(z)`
`T = (2 pi a_(0))/(v_(i)). (n^(3))/(z^(2)), T prop (n^(3))/(z^(2))`
`(T_(2))/(T_(1)) = (n_(2)^(3))/(n_(1)^(3)). (z_(1)^(2))/(z_(2)^(2)) = (8)/(1) xx (1)/(9)`, `T_(2) = (8)/(9) T_(1) = (8)/(9) xx 1.6 xx 10^(-16)`
`T_(2) = 1.42 xx 10^(-16)s`
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