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The radius of gyration of a uniform disc...

The radius of gyration of a uniform disc of radius R, about an axis passing through a point `(R )/(2)` away from the centre of disc, and perpendicular to the plane of disc is:

A

`sqrt((1)/(2)) R`

B

`sqrt(2) R`

C

`(sqrt(3))/(2)R`

D

`(sqrt(3)/(4)) R`

Text Solution

Verified by Experts

The correct Answer is:
C
`I_(AB) = I_(C C') + m ((R )/(2))^(2)`
`I_(AB) = (1)/(2) mR^(2) + (mR^(2))/(4)` , `I_(AB) = (3 mR^(2))/(4)`
`mk^(2) = (3 mR^(2))/(4)` , `k = sqrt((3R^(2))/(4))`
`k = (sqrt(3) R)/(2)`
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