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One gm mol of a diatomic gas (gamma=1.4)...

One gm mol of a diatomic gas `(gamma=1.4)` is compressed adiabatically so that its temperature rises from `27^(@)C` to `127^(@)C` . The work done will be

A

2075 J

B

207.5 J

C

207.5 erG

D

201.1 erg

Text Solution

Verified by Experts

The correct Answer is:
A
`W = - (R )/(gamma - 1) (T_(2) - T_(1))`, `W = - (8.3 (400 - 300))/(1.4 - 1)`
`W = - (8.3 xx 10)/(0.4)` , `W = - 2075 J`
`:.` Work done on the gas = + 2075 j
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