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Pressure difference between two cross sections of a venturimeter, of area `40 cm^(2)` & `20 cm^(2)` is 480 Pascals.Find the rate of flow of water in the ventrurimeter. ( Density of water `= 1000 Kgm^(-3) ` )

A

`1200 cm^(3) //s`

B

` 1600 sqrt( 2) cm^(3) //s `

C

` 1600cm^(3) //s`

D

` 1200 sqrt( 2) cm^(3) //s`

Text Solution

Verified by Experts

By Bernoullis theorem & equation of continuity
We get,
`P_(1)+ ( 1)/( 2) rho V_(1)^(2) = P_(2) +( 1)/(2) rho V_(2)^(2) ` ….(i)
`A_(1) V_(1) = A_(2) V_(2) =Q` ….(ii)
Substituting the value , we get `Q = 1600 sqrt( 2) cm^(3)//` is
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