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If aperture diameter of telescope is 10m...

If aperture diameter of telescope is 10m and distance Moon and Earth is `4 xx 10^(5) Km`. With wavelength of lightis `5500 Å`. The minimum separation between objects on surface of Moon, so that they are just resolved is close to `:`

A

60 m

B

30 m

C

600 m

D

300 m

Text Solution

Verified by Experts

`theta = 1.22 (lambda)/( D)`
`( x )/( 4 xx 10^(5) xx 10^(3)) = ( 1.22 xx 5500 xx 10^(-10))/( 10) ` , x =26.84 m
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