The electronic configuration of bivalent Europium and trivalent cerium respectively is: (Atomic Number: Xe = 54, Ce = 58, Eu = 63)

Options

A. `[Xe]4f^(8)`and`[Xe] 4f^(13)`
B. `[Xe] 4f^(7)` and `[Xe] 4f^(14)`
C. `[Xe] 4f^(8)6s^(1) ` and `[Xe] 4f^(13) 6s^(1)`
D. `[Xe] 4f^(8) ` and `[ Xe ] 4f^(14)`

Explanation

(i) `Tb =[Xe] 6x^(2) 4f^(9), Tb^(+4) =[Xe] 4f^(7)`
(ii) `Yb =[Xe ]6x^(2) 4f^(14) , Yb^(+2)= [Xe] 4f^(14)`