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Electrolysis of dilute aqueous NaCl solu...

Electrolysis of dilute aqueous `NaCl` solution was carried out by passing `10mA` current. The time required to liberate `0.01mol` of `H_(2)` gas at the cathode is `(1F=96500C mol ^(-1))`

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`2H^(+) +2e^(-) H_(2) rArr 1` mole`H_(2) = ` 2mole `e^(ө)`
0.01 mole of `H_(2) =0.02` mole `e^(ө)`
`0.023 = (Q)/(F) = ( I xxt )/( F ) `, `t = ( 0.02 xx 96500)/(10) =193` sec
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