A carnot engine having an efficiency of `(1)/(5)` is being used as a refrigerator. If the work done on the refrigerator is 8 J, the amount of heat absorbed from the reservoir at lower temperature is:

Options

A. 9 J
B. 32 J
C. 20 J
D. 15 J

Answer

B

Explanation

Refrigerator cycle is
`n = (W)/(Q_(+)) = (W)/(W + Q)`
`(1)/(5) = (8)/(8 + Q) , Q = 32 J`
Heat absorbed from the reservoir at lower temperature is 32 J.