A ball is dropped from the top of a tower. In the last second of motion it covers `(5)/(9)` th of tower height before hitting the ground. Acceleration due to gravity = 10 (in `ms^(–2))`. Find height of tower (in m):

Explanation

(45) h = `(1)/(2)gt^(2) , (4)/(9) h = (1)/(2) g (t - 1)^(2)`
Solving h = 45 m