The ratio of the radius difference betwe...

The ratio of the radius difference between 4th and 3rd orbit of H-atom and that of `Li^(2+)` is:

A

`1 : 1`

B

`3 : 1`

C

`3 : 4`

D

`9 : 1`

Verified by Experts

The correct Answer is:

B

`r_(4th) - r_(3rd) = (a_(0))/(z) [4^(2) - 3^(2)] therefore r_(H^(+))/(r_(Li^(2+))) = (3)/(1)`

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