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For the cell, Pt|Cl2(g,0.4"bar")|Cl^(-)(...

For the cell, `Pt|Cl_2(g,0.4"bar")|Cl^(-)(aq,0.1M)"||"Cl^(-)(aq),0.01M)|Cl_2(g,0.2"bar")|pt`

Text Solution

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(-0.05) E = `E^(0) - (0.0591)/(2)log""((0.1)^(2)(0.2))/((0.4) (0.01)^(2)), where E^(0) = 0`
solving E = -0.05`
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