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If an ellipse passes through the point P...

If an ellipse passes through the point `P(-3, 3)` and it has vertices at `(+-6, 0)` , then the equation of the normal to it at P is:

A

`3x+y+6=0`

B

`2x+3y -3 =0`

C

`x+3y - 6=0`

D

`x-2y+9=0`

Text Solution

Verified by Experts

The correct Answer is:
A
`x^2 /36 + y^2/b^2 = 1" ...(1)"`
p (-3,3) lies on (1) `b^2=12`
`x^2 /367 + y^2/12 = 1`
Equation of normal is `(a^2x)/x^1 - (b^2 y)/y_1 = a^2 e^2," "3x + y + 6 =0`
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