The differential equation of the family ...

The differential equation of the family of curves,` y^2 = 4a(x+b)(x+b),a,b,in R`, has order and degree respectively equal to :

A

`1.2`

B

`2.1`

C

`2,2`

D

`1,1`

Verified by Experts

The correct Answer is:

B

`2yy'4a rArr y/(2y') = x_b rArr 2 (y')^2 - 2yy'' = 4 (y')^2`
Required D.E. is `(y')^2 + yy'' = 0`
Hence order is 2 & degree is 1

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