The sum, underset(n-1)overset(10)(Sigma)...

The sum, `underset(n-1)overset(10)(Sigma)(n(2n+1)(2n-1))/5` is equal to.........

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The correct Answer is:

2409

`1/5 (underset(nprop1)overset(10)(Sigma)4n^3 - underset(nprop1)overset(10)(Sigma)n) " "1/5 ((n(n+1))^2 -(n(n+1))/2)`
Put ` n =10 = 2409 `

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