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Find the centre of mass of a uniform dis...

Find the centre of mass of `a` uniform disc of radius a from which a circualr section of radius `b` has been removed. The centre of hole is at a distance `c` from the centre of the disc.

A

`(pib^(2))/((a^(2)-b^(2)))`

B

`(-cb^(2))/((a^(2)-b^(2)))`

C

`(pc^(2))/((a^(2)-b^(2)))`

D

`(pia^(2))/((c^(2)-b^(2)))`

Text Solution

Verified by Experts

The correct Answer is:
B
`X_("cm")=(MX-m_(1)x_(1))/(M-m_(1))=(sigma a^(2)(0)-sigmapi b^(2)(c))/(sigma pia^(2)-sigma pib^(2))" "x_(cm)=(-cb^(2))/((a^(2)-b^(2)))`
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